Math Problem Statement

A boat is cruising the ocean off a straight shoreline. Points A and B are 120 miles apart on the shore, as shown. It is found that ∠A = 42.3° and ∠B = 68.9°. Find the distance from the boat to the shore.

Solution

To solve this problem, let's analyze the triangle formed by points AA, BB, and CC, where:

  • Point AA and BB are located along the shoreline.
  • CC is the boat's location in the water.
  • A=42.3\angle A = 42.3^\circ
  • B=68.9\angle B = 68.9^\circ
  • AB=120AB = 120 miles (distance between points AA and BB along the shoreline).

Since we know two angles in the triangle (A\angle A and B\angle B), we can determine the third angle, C\angle C, by using the property that the sum of the angles in a triangle is 180180^\circ.

Step 1: Calculate C\angle C

C=180AB=18042.368.9=68.8\angle C = 180^\circ - \angle A - \angle B = 180^\circ - 42.3^\circ - 68.9^\circ = 68.8^\circ

Step 2: Apply the Law of Sines

We need to find the distance from point CC (the boat) to the shoreline, which is the length ACAC or BCBC. Using the Law of Sines, we have: ABsin(C)=ACsin(B)=BCsin(A)\frac{AB}{\sin(\angle C)} = \frac{AC}{\sin(\angle B)} = \frac{BC}{\sin(\angle A)}

Let's solve for ACAC: AC=ABsin(B)sin(C)AC = \frac{AB \cdot \sin(\angle B)}{\sin(\angle C)}

Step 3: Substitute Known Values

Substitute AB=120AB = 120 miles, B=68.9\angle B = 68.9^\circ, and C=68.8\angle C = 68.8^\circ: AC=120sin(68.9)sin(68.8)AC = \frac{120 \cdot \sin(68.9^\circ)}{\sin(68.8^\circ)}

Using approximate values for the sines: sin(68.9)0.9272andsin(68.8)0.9270\sin(68.9^\circ) \approx 0.9272 \quad \text{and} \quad \sin(68.8^\circ) \approx 0.9270

AC1200.92720.9270120.03 milesAC \approx \frac{120 \cdot 0.9272}{0.9270} \approx 120.03 \text{ miles}

Conclusion

The distance from the boat to the shoreline (along line ACAC) is approximately 120.03 miles.

Would you like a more detailed breakdown or have any questions?


Here are 5 related questions to deepen your understanding:

  1. How would the solution change if the distance ABAB were different?
  2. Can the Law of Cosines be used in this scenario? If so, how?
  3. What other applications does the Law of Sines have in navigation?
  4. How does this problem illustrate the importance of angle measurements in trigonometry?
  5. What if the angle measurements were in radians instead of degrees? How would that affect the solution?

Tip: When solving trigonometric problems involving distances and angles, always double-check angle sum calculations to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Triangle Angle Sum

Formulas

Triangle Angle Sum: ∠A + ∠B + ∠C = 180°
Law of Sines: (a/sin(A)) = (b/sin(B)) = (c/sin(C))

Theorems

Triangle Angle Sum Theorem
Law of Sines

Suitable Grade Level

Grades 10-12