Math Problem Statement
Using the definition of the derivative, find f prime left parenthesis x right parenthesis. Then find f prime left parenthesis 1 right parenthesis, f prime left parenthesis 2 right parenthesis, and f prime left parenthesis 3 right parenthesis when the derivative exists. f(x)equalsnegative x squared plus 5 x minus 9 To find the derivative, complete the limit as h approaches 0 for StartFraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right parenthesis Over h EndFraction .
Solution
To find the derivative of the function using the definition of the derivative, we need to compute the following limit:
Step 1: Compute
Substitute into the function :
Expand this expression: Simplifying:
Step 2: Compute
Now subtract from : Distribute the negative sign: Simplify the terms:
Step 3: Form the difference quotient
Now, divide by : Simplify the expression:
Step 4: Take the limit as
Now take the limit as approaches 0:
Thus, the derivative of is:
Step 5: Find , , and
Summary:
Would you like more details on any of these steps or further explanations?
Related Questions:
- What is the geometric meaning of the derivative at a point?
- How would the second derivative of be computed?
- What is the interpretation of the values , , and ?
- Can we use the power rule to differentiate and get the same result?
- How would the derivative change if the function were ?
Tip: The definition of the derivative is a fundamental concept in calculus that captures the rate of change of a function at any point. It’s crucial for understanding motion, optimization, and various other mathematical applications.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Limits
Quadratic Functions
Formulas
f'(x) = lim(h → 0) [f(x + h) - f(x)] / h
f(x) = -x^2 + 5x - 9
f'(x) = -2x + 5
Theorems
Definition of the Derivative
Limit Theorem
Suitable Grade Level
Grades 11-12, College Introductory Calculus
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