The image you've uploaded contains a question in Vietnamese about geometry in a three-dimensional space. Here's a translation of the problem:

Question 1:
In the space $Oxyz$, given the line $d$ defined by the system: $\frac{x}{2} = \frac{y-1}{1} = \frac{z+1}{1}$ and the plane $(\alpha)$ defined by the equation: $x - 2y - 2z + 5 = 0$ Find the coordinates of the point $A(a; b; c)$ such that the point lies on the line $d$ and the distance from $A$ to the plane $\alpha$ is 3. Calculate $a + b - c$.

Approach:

1. Parameterize the Line $d$:
   The equation for the line $d$ can be written as: $x = 2t, \quad y = 1 + t, \quad z = -1 + t$ where $t$ is the parameter.

2. Substitute Coordinates of $A(a; b; c)$ into the Plane Equation:
   The point $A(a; b; c)$ lies on the line, so substitute the parameterized coordinates into the plane equation: $2t - 2(1 + t) - 2(-1 + t) + 5 = 0$

3. Find the Distance from Point $A$ to Plane $\alpha$:
   The distance $d$ from a point $(x_1, y_1, z_1)$ to the plane $Ax + By + Cz + D = 0$ is given by the formula: $d = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}}$ For this problem, we set $d = 3$ and solve for the coordinates $a, b, c$.

4. Solve for $a + b - c$:
   Once the values for $a$, $b$, and $c$ are found, compute $a + b - c$.

Would you like a detailed solution, or is there a specific step you'd like to focus on?