Math Problem Statement

Find x given a = 56 in a right triangle with angles 63° and 39°.

Solution

In this problem, we have a right triangle with the following information:

  • Angle 6363^\circ at the base left corner.
  • Angle 3939^\circ at the base right corner.
  • The length of the height a=56a = 56, perpendicular to the base xx.
  • We are tasked with finding the base xx, rounded to the nearest hundredth.

Approach:

We can use trigonometric functions to solve this. Since aa is the opposite side to the angle 6363^\circ and xx is the adjacent side, we can use the tangent function:

tan(63)=oppositeadjacent=ax\tan(63^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{a}{x}

Substituting the known values:

tan(63)=56x\tan(63^\circ) = \frac{56}{x}

Solving for xx:

x=56tan(63)x = \frac{56}{\tan(63^\circ)}

Let me compute this.The length of the base xx is approximately 28.5328.53, rounded to the nearest hundredth.

Do you want more details or have any questions about the solution?

Here are 5 related questions to expand your understanding:

  1. How would you solve for xx if aa were unknown and only the angles and xx were given?
  2. What trigonometric function would you use if the angle given was at the base of the triangle?
  3. How can you check if your solution for xx is correct using another trigonometric function?
  4. What is the relation between the angles and sides in a right triangle?
  5. How could the Pythagorean theorem be applied if both legs were known?

Tip: When using trigonometric functions, always ensure your calculator or software is set to the correct mode (degrees or radians) based on the problem’s given angle units.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangle
Tangent Function

Formulas

tan(θ) = opposite/adjacent

Theorems

Trigonometric Ratios in Right Triangles

Suitable Grade Level

Grades 9-11