Math Problem Statement

In the adjoining figure, the ratio of the sides of the two squares ABCD and PQRC is 3:1. Also, AR = 24 cm. Find the area of square PQRS.

Solution

The problem shows two squares ABCDABCD and PQRCPQRC with the ratio of their sides as 3:13:1. We are given the diagonal ARAR of AR\triangle AR as 2424 cm. The task is to find the area of square PQRSPQRS.

Step-by-Step Solution:

  1. Side of the Larger Square ABCDABCD: Let's assume the side of the larger square ABCDABCD is 3x3x. Since the ratio of sides is 3:13:1, the side of the smaller square PQRCPQRC will be xx.

  2. Diagonal Calculation: The diagonal

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Math Problem Analysis

Mathematical Concepts

Geometry
Ratio and Proportion
Squares
Pythagorean Theorem

Formulas

Area of square = side^2
Pythagorean theorem for diagonal: diagonal^2 = side1^2 + side2^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-10