The image shows a trapezoid with a height of $2x$ and a base of $3x$. To find the area of the trapezoid, you would generally use the formula:

$\text{Area} = \frac{1}{2} \times \text{height} \times (\text{Base}_1 + \text{Base}_2)$

However, since I cannot see all the information (such as the second base), I will assume it's not fully provided in the image. If the shape is not a trapezoid but another type of quadrilateral, such as a parallelogram, we can use the formula for the area of a parallelogram:

$\text{Area} = \text{base} \times \text{height}$

From the image:

• Base = $3x$
• Height = $2x$

So, the area would be:

$\text{Area} = 3x \times 2x = 6x^2$

Let me know if this interpretation is correct or if there is more detail needed.

Would you like more explanation, or are there additional details from the image that I missed?

Here are 5 follow-up questions related to this concept:

1. How do we modify the formula for finding the area of a trapezoid if both bases are given?
2. How does the area of a parallelogram change when the height or base is doubled?
3. How can you simplify the area formula if the height or base includes a polynomial expression?
4. What is the difference in approach when calculating areas for irregular shapes compared to regular quadrilaterals?
5. How would you approach the problem if the figure was a triangle instead of a parallelogram?

Tip: Always make sure to double-check if the shape provided has all sides or only part of them before applying area formulas.