Math Problem Statement

Two parallel lines are cut by a transversal. Suppose m∠8 = 139°. Find m∠2 and m∠3.

Solution

The problem asks to find the measures of angles 2\angle 2 and 3\angle 3 given that two parallel lines are cut by a transversal, and m8=139m \angle 8 = 139^\circ.

Step-by-Step Solution:

  1. Identify Angle Relationships:

    • Since the lines are parallel and cut by a transversal, we can apply properties such as alternate interior angles, corresponding angles, and supplementary angles.
    • 8\angle 8 and 3\angle 3 are alternate interior angles. Since alternate interior angles are equal when lines are parallel: m3=m8=139m \angle 3 = m \angle 8 = 139^\circ
  2. Use Supplementary Angle Property:

    • Angles on a straight line are supplementary, meaning they add up to 180180^\circ.
    • 2\angle 2 and 8\angle 8 are supplementary because they form a linear pair: m2+m8=180m \angle 2 + m \angle 8 = 180^\circ Substituting m8=139m \angle 8 = 139^\circ: m2+139=180m \angle 2 + 139^\circ = 180^\circ Solving for m2m \angle 2: m2=180139=41m \angle 2 = 180^\circ - 139^\circ = 41^\circ

Final Answer:

  • m2=41m \angle 2 = 41^\circ
  • m3=139m \angle 3 = 139^\circ

Do you want any further details or explanations? Here are five questions that extend this topic:

  1. What are alternate exterior angles, and how do they relate in parallel lines?
  2. Can you describe the relationship between corresponding angles?
  3. How do vertical angles behave when parallel lines are cut by a transversal?
  4. If the measure of 1\angle 1 is known, how can you find 7\angle 7?
  5. What is the significance of supplementary angles in geometric proofs?

Tip: Always identify the angle relationships (alternate, corresponding, or supplementary) when working with parallel lines and a transversal to simplify solving the problem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Parallel Lines
Transversals
Angles

Formulas

Supplementary angles: m∠2 + m∠8 = 180°

Theorems

Alternate Interior Angles Theorem
Linear Pair Postulate

Suitable Grade Level

Grades 6-8