Math Problem Statement

given that α+β\alpha+\beta=4 and αβ \alpha\beta\text{ }=10. Find the value of α2+β2\alpha^2+\beta^2

Solution

To find the value of α2+β2\alpha^2 + \beta^2, we can use the identities involving sums and products of roots.

Given:

  1. α+β=4\alpha + \beta = 4
  2. αβ=10\alpha \beta = 10

The identity for α2+β2\alpha^2 + \beta^2 in terms of α+β\alpha + \beta and αβ\alpha \beta is: α2+β2=(α+β)22αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2 \alpha \beta

Step-by-Step Calculation

  1. Substitute α+β=4\alpha + \beta = 4 and αβ=10\alpha \beta = 10 into the formula: α2+β2=(4)2210\alpha^2 + \beta^2 = (4)^2 - 2 \cdot 10
  2. Calculate (4)2(4)^2: (4)2=16(4)^2 = 16
  3. Calculate 2102 \cdot 10: 210=202 \cdot 10 = 20
  4. Substitute back: α2+β2=1620=4\alpha^2 + \beta^2 = 16 - 20 = -4

Conclusion

The value of α2+β2\alpha^2 + \beta^2 is: α2+β2=4\alpha^2 + \beta^2 = -4

Would you like further clarification or have additional questions?


Here are five related questions to deepen your understanding:

  1. What is the value of α3+β3\alpha^3 + \beta^3 given α+β=4\alpha + \beta = 4 and αβ=10\alpha \beta = 10?
  2. How can you find (αβ)2(\alpha - \beta)^2 using α+β\alpha + \beta and αβ\alpha \beta?
  3. If α\alpha and β\beta are roots of a quadratic equation, what would the equation be?
  4. How does the sign of αβ\alpha \beta affect the value of α2+β2\alpha^2 + \beta^2?
  5. Can α\alpha and β\beta be real numbers with the given values of α+β\alpha + \beta and αβ\alpha \beta?

Tip: When working with sum and product identities, try to remember key formulas like α2+β2=(α+β)22αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta for quick calculations.

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Math Problem Analysis

Mathematical Concepts

Algebra
Sum and Product of Roots
Polynomial Identities

Formulas

\( \alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2 \alpha \beta \)

Theorems

Polynomial Identities
Basic Algebraic Identities

Suitable Grade Level

Grades 9-11