To find the zeros of the function $f(x) = (x - 10)^2 - 49$, we need to solve the equation $f(x) = 0$. This means we set the function equal to zero and solve for $x$.

$(x - 10)^2 - 49 = 0$

First, add 49 to both sides of the equation:

$(x - 10)^2 = 49$

Next, take the square root of both sides:

$x - 10 = \pm \sqrt{49}$

Since $\sqrt{49} = 7$, we have:

$x - 10 = \pm 7$

This gives us two possible equations:

1. $x - 10 = 7$
2. $x - 10 = -7$

Solve each equation:

1. $x = 7 + 10 = 17$
2. $x = -7 + 10 = 3$

So, the zeros of the function are $x = 3$ and $x = 17$.

Thus, the solutions from least to greatest are: $\boxed{3 \text{ and } 17}$

Would you like any details or have any questions?

Here are five related questions for further practice:

1. Find the zeros of $f(x) = (x + 5)^2 - 16$.
2. Solve the equation $(x - 4)^2 - 25 = 0$.
3. Determine the zeros of the function $g(x) = (x - 2)^2 - 36$.
4. Find the solutions to the equation $h(x) = (x + 8)^2 - 64$.
5. Solve for $x$ in $(x - 1)^2 - 9 = 0$.

Tip: Always remember that taking the square root of both sides of an equation introduces both the positive and negative roots.