The image you uploaded shows a request to find the z-score that corresponds to the 82nd percentile (P82) using the standard normal table.

To find the z-score for P82:

1. Look up the closest area (probability) of 0.8200 in the z-table.
2. Find the corresponding z-score for this area.

Based on the standard normal distribution table, the z-score corresponding to the cumulative area of 0.8200 is approximately 0.92.

So, the z-score corresponding to P82 is 0.92.

Let me know if you'd like further details or if you have other questions!

Related Questions:

1. How do I interpret a z-score in terms of the standard normal distribution?
2. How would I find the z-score for a percentile like P90 or P95?
3. What is the relationship between z-scores and probabilities in normal distribution?
4. How do you use a z-table to find areas under the normal curve?
5. What is the concept of the area in the standard normal table?

Tip: When finding z-scores, it's always helpful to round to two decimal places for clarity and consistency.