To find the y-intercept of the function \( f(x) = -2x^2 + 12x - 16 \), we need to evaluate \( f(0) \):

\[
f(0) = -2(0)^2 + 12(0) - 16 = -16
\]

Thus, the y-intercept is \( (0, -16) \).

If you have any questions or need further details, let me know! Here are some related questions you might consider:

1. How do you find the x-intercepts of this function?
2. What does the graph of this quadratic function look like?
3. Can you explain how to determine the vertex of this parabola?
4. How would the y-intercept change if the equation were different?
5. What is the significance of the coefficients in the quadratic equation?

**Tip:** Remember that the y-intercept is the point where the graph crosses the y-axis, which occurs when \( x = 0 \).

Discover how to find the y-intercept of the quadratic function f(x) = -2x^2 + 12x - 16 by evaluating f(0). This solution includes a step-by-step guide, relevant concepts in quadratic functions, and is ideal for students in Grades 9-10.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation