Math Problem Statement

For a data set on x and y, the value of is 𝑆𝑆π‘₯π‘₯ 546, is 𝑆𝑆π‘₯𝑦 -1484, the mean of the x values is 30, and the mean of the y values is 76. The value of a in the regression of y on x, rounded to two decimal places, is:

Solution

To find the value of aa (the y-intercept) in the regression equation of yy on xx, we can use the following formula:

y=a+bxy = a + bx

where:

  • aa is the y-intercept.
  • bb is the slope of the regression line and is calculated by the formula:

b=SSxySSxxb = \frac{SS_{xy}}{SS_{xx}}

Given Data

  • SSxx=546SS_{xx} = 546
  • SSxy=βˆ’1484SS_{xy} = -1484
  • Mean of xx values, xΛ‰=30\bar{x} = 30
  • Mean of yy values, yΛ‰=76\bar{y} = 76

Step 1: Calculate the Slope, bb

b=SSxySSxx=βˆ’1484546b = \frac{SS_{xy}}{SS_{xx}} = \frac{-1484}{546}

Calculating this gives:

bβ‰ˆβˆ’2.72b \approx -2.72

Step 2: Calculate the Intercept, aa

Now we can use the formula for aa:

a=yΛ‰βˆ’bβ‹…xΛ‰a = \bar{y} - b \cdot \bar{x}

Substitute the values:

a=76βˆ’(βˆ’2.72)β‹…30a = 76 - (-2.72) \cdot 30

Calculate this:

aβ‰ˆ76+81.6=157.6a \approx 76 + 81.6 = 157.6

Final Answer

The value of aa, rounded to two decimal places, is:

a=157.6a = 157.6

Would you like further details on any step?


  1. How does changing SSxySS_{xy} impact the intercept and slope?
  2. Why is the slope important in interpreting regression results?
  3. How does rounding impact regression accuracy?
  4. What is the role of means in finding intercepts?
  5. How is regression different from correlation?

Tip: In regression, always interpret the slope to understand the relationship between variables fully.

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Math Problem Analysis

Mathematical Concepts

Regression Analysis
Linear Algebra
Statistics

Formulas

Slope (b) = SSxy / SSxx
Intercept (a) = yΜ„ - b * xΜ„

Theorems

Linear Regression Formula

Suitable Grade Level

Grades 10-12