https://file.aiquickdraw.com/mathbot/file/1726918715076fw04f6e2.jpg

The equation of the line provided is:

\[
y + 5 = 6x + 13
\]

We need to determine the value of \( y \) at the point where the line crosses the \( y \)-axis. At the \( y \)-axis, the value of \( x \) is always 0.

### Step 1: Substitute \( x = 0 \) into the equation

\[
y + 5 = 6(0) + 13
\]
\[
y + 5 = 13
\]

### Step 2: Solve for \( y \)

\[
y = 13 - 5
\]
\[
y = 8
\]

Thus, the value of \( y \) when the line crosses the \( y \)-axis is **8**.

Would you like more details or further explanations?

Here are five related questions:
1. How do you find the slope of the line from this equation?
2. What is the general form of a linear equation?
3. How do you find the \( x \)-intercept of the line?
4. Can you express the equation in slope-intercept form \( y = mx + b \)?
5. What does the slope of the line represent in this context?

**Tip:** When a line crosses the \( y \)-axis, \( x \) is always 0, which makes finding the \( y \)-intercept straightforward.

What is the value of y at the point where the line crosses the y-axis? The equation of the line is y + 5 = 6x + 13.

Solve for the y-intercept where the line y + 5 = 6x + 13 crosses the y-axis. A clear step-by-step guide for students in Grades 8-10 covering linear equations and intercepts.

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