The equation of the line provided is:

$y + 5 = 6x + 13$

We need to determine the value of $y$ at the point where the line crosses the $y$-axis. At the $y$-axis, the value of $x$ is always 0.

Step 1: Substitute $x = 0$ into the equation

$y + 5 = 6(0) + 13$ $y + 5 = 13$

Step 2: Solve for $y$

$y = 13 - 5$ $y = 8$

Thus, the value of $y$ when the line crosses the $y$-axis is 8.

Would you like more details or further explanations?

Here are five related questions:

1. How do you find the slope of the line from this equation?
2. What is the general form of a linear equation?
3. How do you find the $x$-intercept of the line?
4. Can you express the equation in slope-intercept form $y = mx + b$?
5. What does the slope of the line represent in this context?

Tip: When a line crosses the $y$-axis, $x$ is always 0, which makes finding the $y$-intercept straightforward.