I see that you've uploaded an image of a quiz review question. Let me transcribe and help you solve it.

From the image, the problem appears to be:

Given the equation $y = \frac{x-1}{x+1}$, find the following:

1. The x-intercept.
2. The y-intercept.

Solution:

Let's solve this step by step.

1. Finding the x-intercept:

The x-intercept occurs where $y = 0$. So, set the equation equal to zero:

$0 = \frac{x-1}{x+1}$

For the fraction to be zero, the numerator must be zero. So:

$x - 1 = 0$

$x = 1$

Thus, the x-intercept is $x = 1$.

2. Finding the y-intercept:

The y-intercept occurs where $x = 0$. So, substitute $x = 0$ into the equation:

$y = \frac{0 - 1}{0 + 1} = \frac{-1}{1} = -1$

Thus, the y-intercept is $y = -1$.

Final Answer:

• x-intercept: $x = 1$
• y-intercept: $y = -1$

Would you like further clarification or more details on this?

Here are 5 additional related questions to practice:

1. How do you find the x-intercept of a quadratic equation?
2. What happens to the intercepts if the equation is $y = \frac{x+2}{x-3}$?
3. How do you determine the vertical asymptotes of rational functions like this one?
4. What is the domain of the function $y = \frac{x-1}{x+1}$?
5. How do the intercepts change if the function was $y = \frac{2x-3}{x+4}$?

Tip: To find the x-intercept of a function, always set $y = 0$ and solve for $x$.