The equation of the line is $y = 3x - 9$. To find the intercepts, follow these steps:

1. Finding the y-intercept:

The y-intercept is where the line crosses the y-axis, which occurs when $x = 0$.

• Substitute $x = 0$ into the equation: $y = 3(0) - 9 = -9$ So, the y-intercept is $(0, -9)$.

2. Finding the x-intercept:

The x-intercept is where the line crosses the x-axis, which occurs when $y = 0$.

• Set $y = 0$ in the equation: $0 = 3x - 9$
  • Add 9 to both sides: $9 = 3x$
  • Divide by 3: $x = 3$ So, the x-intercept is $(3, 0)$.

Summary:

• The y-intercept is $(0, -9)$.
• The x-intercept is $(3, 0)$.

Would you like more details or have any questions?

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Here are 5 related questions:

1. What does the slope of this line represent geometrically?
2. How would the intercepts change if the equation was $y = 3x + 9$?
3. What is the slope of a line parallel to $y = 3x - 9$?
4. How do we find the x-intercept in a quadratic equation?
5. Can a line have more than one x-intercept?

Tip: The x-intercept occurs where the line crosses the x-axis, so the y-value is always 0 at that point.