Math Problem Statement

Point B is between points A and C. AC=10x+6, AB=5x, and BC=4x+12. Find the value of x.

Solution

To solve this problem, let's break it down step-by-step:

We are given:

  • AC = 10x+610x + 6
  • AB = 5x5x
  • BC = 4x+124x + 12

Since point B is between points A and C, the sum of AB and BC must be equal to AC: AB+BC=ACAB + BC = AC

Substitute the given values: 5x+(4x+12)=10x+65x + (4x + 12) = 10x + 6

Now, simplify and solve for xx: 5x+4x+12=10x+65x + 4x + 12 = 10x + 6 9x+12=10x+69x + 12 = 10x + 6

Move all terms involving xx to one side and constants to the other side: 9x10x=6129x - 10x = 6 - 12 x=6-x = -6

Divide by -1: x=6x = 6

Thus, the value of xx is 6.

Answer: x=6x = 6.

Would you like further details or have any questions about this solution?

Here are 5 related questions for practice:

  1. If AC = 15x+215x + 2, AB = 3x3x, and BC = 12x+212x + 2, what is the value of xx?
  2. What happens to the equation if AB=5x+3AB = 5x + 3 instead of 5x5x?
  3. How do you solve for xx if AC, AB, and BC were in terms of quadratic expressions?
  4. Can you solve a similar problem if B is not exactly between A and C but some distance away?
  5. How would this problem change if the segments were part of a geometric figure like a triangle?

Tip:

Always simplify both sides of the equation as much as possible before moving terms around to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Segment Addition Postulate

Formulas

AB + BC = AC

Theorems

Segment Addition Theorem

Suitable Grade Level

Grades 8-10