It looks like there's a typo in the equation. The equation seems to be meant as one equation rather than two. Based on the format, I believe the correct equation might be:

\[ 7x + 4y - 3 = 3x + 1 \]

I'll solve for \( x \) in terms of \( y \) using this equation:

1. Start with the given equation:
   \[
   7x + 4y - 3 = 3x + 1
   \]

2. Move all the terms involving \( x \) to one side by subtracting \( 3x \) from both sides:
   \[
   7x - 3x + 4y - 3 = 1
   \]
   Simplifying the equation:
   \[
   4x + 4y - 3 = 1
   \]

3. Now, isolate the \( x \)-terms by moving the non-\( x \) terms to the other side. Add 3 to both sides:
   \[
   4x + 4y = 4
   \]

4. Subtract \( 4y \) from both sides to isolate \( 4x \):
   \[
   4x = 4 - 4y
   \]

5. Finally, solve for \( x \) by dividing both sides by 4:
   \[
   x = 1 - y
   \]

So, \( x \) in terms of \( y \) is:

\[
\boxed{x = 1 - y}
\]

Would you like more details on any of these steps or have any further questions?

Here are five related questions you might consider:

1. How would you solve for \( y \) in terms of \( x \) given the same equation?
2. What happens to the value of \( x \) when \( y = 0 \)?
3. How can you graph the equation \( x = 1 - y \)?
4. What is the significance of the slope in the equation \( x = 1 - y \)?
5. How would the equation change if the constant on the right side was different?

**Tip:** When solving linear equations, always aim to isolate the variable of interest by moving terms across the equation systematically.

Learn how to find x in terms of y in the linear equation 7x + 4y - 3 = 3x + 1. This problem covers solving linear equations and isolating variables. Suitable for students in Grades 7-9.

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