https://file.aiquickdraw.com/mathbot/file/17263065070430pdrptlv.jpg

The problem you've uploaded reads:

*The length of the sides of a right-angled triangle is \( (2x + 1) \) cm and \( x \) cm. Find \( x \) if \( 2x + 1 \) is the hypotenuse.*

We can solve this using the Pythagorean theorem, which states:

\[
\text{(hypotenuse)}^2 = \text{(leg 1)}^2 + \text{(leg 2)}^2
\]

Given:
- Hypotenuse = \( 2x + 1 \)
- One leg = \( x \)
- Other leg = \( \text{unknown} \)

From the problem, it seems we are missing the length of the second leg, but it appears to be one of two standard setups:

1. If the sides are \( x \) and \( x \), then both legs are equal to \( x \).
2. If the side lengths are \( x \) and something like \( 2x \), we would need clarification.

Since you haven't mentioned the second leg clearly, let me know if you'd like to confirm or if the second leg is missing from the image.

I will continue with assumption (1), where both legs are equal, and we can set up the equation:

\[
(2x + 1)^2 = x^2 + x^2
\]

Let me know if you'd like me to proceed with solving this!

The length of the sides of a right-angled triangle is (2x + 1) cm and x cm. Find x if 2x + 1 is the hypotenuse.

Solve the right-angled triangle problem where the hypotenuse is (2x + 1) cm and one leg is x cm. Using the Pythagorean Theorem, learn to form and solve a quadratic equation to find x. Suitable for students in Grades 8-10.

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