The problem you've uploaded reads:

The length of the sides of a right-angled triangle is $(2x + 1)$ cm and $x$ cm. Find $x$ if $2x + 1$ is the hypotenuse.

We can solve this using the Pythagorean theorem, which states:

$\text{(hypotenuse)}^2 = \text{(leg 1)}^2 + \text{(leg 2)}^2$

Given:

• Hypotenuse = $2x + 1$
• One leg = $x$
• Other leg = $\text{unknown}$

From the problem, it seems we are missing the length of the second leg, but it appears to be one of two standard setups:

1. If the sides are $x$ and $x$, then both legs are equal to $x$.
2. If the side lengths are $x$ and something like $2x$, we would need clarification.

Since you haven't mentioned the second leg clearly, let me know if you'd like to confirm or if the second leg is missing from the image.

I will continue with assumption (1), where both legs are equal, and we can set up the equation:

$(2x + 1)^2 = x^2 + x^2$

Let me know if you'd like me to proceed with solving this!