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The problem involves a rider being pulled by a boat during parasailing. To solve for the weight of the rider, we can use the given information:

- Tension in the rope: \( T = 2300 \, \text{N} \)
- The rope is at an angle of \( 15^\circ \) from the horizontal.
- The force of the sail is at an angle of \( 30^\circ \) from the horizontal.

We will assume the rider is in equilibrium, meaning that the forces in both the horizontal and vertical directions must balance.

### Step 1: Vertical Force Balance
The weight of the rider acts vertically downward and is balanced by the vertical components of both the tension in the rope and the force from the sail. The vertical component of the tension is:
\[
T_{\text{vertical}} = T \sin(15^\circ)
\]
Thus, the weight of the rider \( W \) is given by the equation:
\[
W = T \sin(15^\circ)
\]

### Step 2: Calculation
Now, we can plug in the values:

\[
W = 2300 \times \sin(15^\circ)
\]

Using a calculator, we find:
\[
W \approx 2300 \times 0.2588 = 595.24 \, \text{N}
\]

So, the weight of the rider is approximately **595 N**.

Would you like further details or clarifications on this solution?

Here are some additional questions to expand on this topic:
1. What other forces act on the rider in a parasailing situation?
2. How would the problem change if the tension in the rope were different?
3. What is the role of the angle of the sail in this problem?
4. How would you calculate the horizontal component of the forces?
5. What would happen if the boat's speed were to increase?

**Tip:** Always break forces into components when dealing with angles, especially in equilibrium problems.

In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A rider is towed at a constant speed by a rope that is at an angle of 15° from horizontal. The tension in the rope is 2300 N. The force of the sail on the rider is 30° from horizontal. What is the weight of the rider?

Solve a parasailing problem where a rider is pulled by a boat using a rope at an angle of 15° with a tension of 2300 N. Learn how to apply trigonometry and equilibrium of forces to calculate the weight of the rider. Suitable for students in Grades 10-12.

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