Math Problem Statement

A square of side 2 units has one vertex at (0,0) and one diagonal along the x-axis. What are the coordinates of the three vertices?

Solution

To solve this problem, we need to determine the coordinates of the three remaining vertices of a square with a side length of 22 units, given that one vertex is at (0,0)(0, 0) and one of its diagonals is along the x-axis.

Explanation:

  1. Square Properties:

    • A square has four sides of equal length and diagonals that bisect each other at right angles (90 degrees).
    • Given that one diagonal is along the x-axis, the center of the square will lie on the x-axis, and the diagonals will be perpendicular.
  2. Diagonal Length:

    • The length of a diagonal of a square with a side length s=2s = 2 is given by: Diagonal length=s2=22\text{Diagonal length} = s\sqrt{2} = 2\sqrt{2}
  3. Finding the Center:

    • Since one vertex is at (0,0)(0, 0), and the diagonal is along the x-axis, the center of the square will lie at the midpoint of the diagonal. Thus, the center of the square is at (s2/2,0)=(2,0)(s\sqrt{2}/2, 0) = (\sqrt{2}, 0).
  4. Determining the Vertices:

    • The vertices of the square can be found by rotating around the center (2,0)(\sqrt{2}, 0) by 45 degrees (since the diagonals are perpendicular bisectors).

    Using the rotation formula around the center: (x,y)=(xc+(xxc)cosθ(yyc)sinθ,  yc+(xxc)sinθ+(yyc)cosθ)(x', y') = (x_c + (x - x_c) \cos \theta - (y - y_c) \sin \theta, \; y_c + (x - x_c) \sin \theta + (y - y_c) \cos \theta) For a 45-degree rotation (θ=45\theta = 45^\circ):

    • First vertex: Rotating (0,0)(0, 0) by 45 degrees around (2,0)(\sqrt{2}, 0) gives (2,2)(\sqrt{2}, \sqrt{2}).
    • Second vertex: Rotating (22,0)(2\sqrt{2}, 0) by 45 degrees around (2,0)(\sqrt{2}, 0) gives (2,2)(\sqrt{2}, -\sqrt{2}).
    • The third vertex is already given by the end of the diagonal at (22,0)(2\sqrt{2}, 0).
  5. Final Coordinates: The coordinates of the three other vertices are:

    • (2,2)(\sqrt{2}, \sqrt{2})
    • (2,2)(\sqrt{2}, -\sqrt{2})
    • (22,0)(2\sqrt{2}, 0)

These match the answer provided in the image.

Would you like further details or have any questions?

Here are some related questions for further exploration:

  1. What is the equation of a circle circumscribed around this square?
  2. How do we find the coordinates of a point after rotating it about another point?
  3. How can we determine the coordinates of the vertices of a rectangle instead of a square given one diagonal?
  4. What are the properties of a square's diagonals in coordinate geometry?
  5. How would the answer change if the side length of the square were different?

Tip: When dealing with coordinate geometry problems involving rotations, always remember to use the rotation formulas or visualize the problem geometrically on a graph.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Rotation
Square Properties

Formulas

Diagonal length of a square = side * sqrt(2)
Rotation formula (x', y') = (x_c + (x - x_c) cos θ - (y - y_c) sin θ, y_c + (x - x_c) sin θ + (y - y_c) cos θ)

Theorems

Properties of a square
Pythagorean Theorem

Suitable Grade Level

Grades 9-12