Math Problem Statement

Find all horizontal and vertical asymptotes of r(x) = (7x^2 + 6x) / (x^4 - 1).

Solution

Let's solve the problem of finding the horizontal and vertical asymptotes for the given rational function:

r(x)=7x2+6xx41r(x) = \frac{7x^2 + 6x}{x^4 - 1}

Step 1: Find Vertical Asymptotes

Vertical asymptotes occur where the denominator is zero, provided that the numerator is not zero at those points.

Set the denominator equal to zero:

x41=0x^4 - 1 = 0

This equation can be factored as:

(x21)(x2+1)=0(x^2 - 1)(x^2 + 1) = 0

Further factor x21x^2 - 1:

(x1)(x+1)(x2+1)=0(x - 1)(x + 1)(x^2 + 1) = 0

Thus, the solutions are:

x1=0x=1x - 1 = 0 \quad \Rightarrow \quad x = 1 x+1=0x=1x + 1 = 0 \quad \Rightarrow \quad x = -1

x2+1=0x^2 + 1 = 0 gives:

x2=1x=±i(complex roots, so ignore)x^2 = -1 \quad \Rightarrow \quad x = \pm i \quad (\text{complex roots, so ignore})

Therefore, the vertical asymptotes are at x=1x = 1 and x=1x = -1.

Step 2: Find Horizontal Asymptotes

Horizontal asymptotes depend on the degrees of the numerator and the denominator:

  • If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y=0y = 0.
  • If the degree of the numerator equals the degree of the denominator, the horizontal asymptote is y=leading coefficient of numeratorleading coefficient of denominatory = \frac{\text{leading coefficient of numerator}}{\text{leading coefficient of denominator}}.
  • If the degree of the numerator is greater than the degree of the denominator, there is no horizontal asymptote.

For r(x)=7x2+6xx41r(x) = \frac{7x^2 + 6x}{x^4 - 1}:

  • The degree of the numerator 7x2+6x7x^2 + 6x is 2.
  • The degree of the denominator x41x^4 - 1 is 4.

Since the degree of the numerator (2) is less than the degree of the denominator (4), the horizontal asymptote is:

y=0y = 0

Final Answer:

  • Vertical Asymptotes: x=1x = 1, x=1x = -1
  • Horizontal Asymptote: y=0y = 0

Would you like more details on any of these steps or have any further questions?

Here are some related questions:

  1. How would the horizontal asymptote change if the degrees of the numerator and denominator were equal?
  2. Can a function have more than one horizontal asymptote? Why or why not?
  3. What happens to the function r(x)r(x) as xx approaches infinity?
  4. How do complex roots affect the location of vertical asymptotes?
  5. Can there be a situation where the function has no asymptotes at all?

Tip: When finding vertical asymptotes, always check for any common factors between the numerator and denominator that might cancel out. This could lead to holes in the graph rather than asymptotes.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Asymptotes
Factoring
Polynomials

Formulas

Horizontal Asymptotes: Degree of numerator < Degree of denominator => y = 0
Vertical Asymptotes: Denominator = 0, solve for x

Theorems

If degree of numerator is less than degree of denominator, the horizontal asymptote is y = 0
Vertical asymptotes occur where the denominator equals zero, provided the numerator is non-zero

Suitable Grade Level

Grades 10-12