The graph you've provided represents a linear function $f(x)$. Based on the slope and the points visible on the graph, I can help determine the values of $f(x)$ for specific inputs.

1. $f(0)$:

   • This is the value of the function when $x = 0$, which corresponds to the y-intercept of the line.
   • From the graph, it appears that the line crosses the y-axis at $y = 1$.
   • Therefore, $f(0) = 1$.

2. $f(-1)$:

   • To find $f(-1)$, locate $x = -1$ on the x-axis and find the corresponding y-value on the line.
   • From the graph, when $x = -1$, $y = 0$.
   • Therefore, $f(-1) = 0$.

3. $f(2)$:

   • To find $f(2)$, locate $x = 2$ on the x-axis and find the corresponding y-value on the line.
   • From the graph, when $x = 2$, $y = 3$.
   • Therefore, $f(2) = 3$.

4. $f(-2)$:

   • To find $f(-2)$, locate $x = -2$ on the x-axis and find the corresponding y-value on the line.
   • From the graph, when $x = -2$, $y = -1$.
   • Therefore, $f(-2) = -1$.

Summary:

1. $f(0) = 1$
2. $f(-1) = 0$
3. $f(2) = 3$
4. $f(-2) = -1$

Would you like more details on how to derive these values, or do you have any questions?

Here are some related questions you might consider:

1. What is the slope of the function shown in the graph?
2. Can you derive the equation of the line from the graph?
3. How would you find $f(x)$ for other values of $x$ not explicitly asked?
4. How does changing the slope of the line affect the graph and the function's values?
5. What happens to the graph if you change the y-intercept?

Tip: For linear functions, identifying the slope and y-intercept allows you to determine the function's equation and predict values for any input $x$.