Math Problem Statement
Solution
We are given two equations in the problem:
- The line: , where is a constant.
- The parabola: .
The goal is to find the value of such that the line and the parabola intersect at exactly one point.
Step 1: Express the line equation in terms of
From the equation , solve for :
Step 2: Set the equations equal to each other
Since both equations describe , set the right-hand side of the parabola equal to the right-hand side of the line equation:
Multiply both sides of the equation by 2 to eliminate the fraction:
Step 3: Rearrange the equation
Rearrange the equation into a standard quadratic form:
Step 4: Use the condition for exactly one intersection
For the line to intersect the parabola at exactly one point, the quadratic equation must have exactly one solution. This happens when the discriminant is zero. The discriminant for a quadratic equation is given by:
Here, the quadratic equation is:
Thus, , , and . The discriminant is:
Simplifying:
Set the discriminant equal to zero for exactly one solution:
Step 5: Solve for
Thus, the value of is .
Would you like further explanation on any step? Here are some related questions for further exploration:
- How does the discriminant determine the number of solutions to a quadratic equation?
- What happens if the discriminant is positive or negative?
- How do we handle cases where the intersection results in two points instead of one?
- Can this method be extended to other types of curves, such as ellipses or hyperbolas?
- How would the result change if the line equation was different, such as ?
Tip: When solving systems of equations with parabolas, always consider the discriminant for determining the nature of intersections!
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Math Problem Analysis
Mathematical Concepts
Algebra
Quadratic Equations
Parabolas
Lines
Formulas
Discriminant of a quadratic equation
y = ax^2 + bx + c
Theorems
Quadratic discriminant condition (b^2 - 4ac = 0 for one solution)
Suitable Grade Level
Grades 10-12
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