https://file.aiquickdraw.com/mathbot/file/1727206077769b0ljkj28.jpg

Let's work through the two parts of the problem.

**a) Find the value of \( 1 + 3x \) when \( x = 1 \):**

We simply substitute \( x = 1 \) into the expression:
\[
1 + 3x = 1 + 3(1) = 1 + 3 = 4
\]
So, the value is **4**.

**b) Find the value of \( 7 - 2x \) when \( x = -3 \):**

Again, substitute \( x = -3 \) into the expression:
\[
7 - 2x = 7 - 2(-3) = 7 + 6 = 13
\]
So, the value is **13**.

Would you like further details or explanations?

Here are five follow-up questions:
1. What is the result of \( 2x + 5 \) when \( x = 4 \)?
2. How does the value of \( 1 + 3x \) change if \( x = -2 \)?
3. What happens to \( 7 - 2x \) when \( x = 0 \)?
4. How do you evaluate expressions with negative values of \( x \)?
5. What is the process for solving for \( x \) in more complex expressions?

**Tip:** Always substitute carefully and simplify the expression step-by-step to avoid mistakes.

a) Find the value of 1 + 3x when x = 1.
b) Find the value of 7 - 2x when x = -3.

Learn how to evaluate the linear expressions 1 + 3x when x = 1 and 7 - 2x when x = -3. This problem covers key algebraic concepts suitable for Grades 6-8.

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