The problem in the image asks to calculate the value of four algebraic expressions for two different values of $x$:

1. $x = 5$
2. $x = -3$

The expressions are:

1. $-8x$
2. $4x + 7$
3. $16 - 2x$
4. $\frac{x - 5}{2}$

Let's evaluate each of these expressions for both $x = 5$ and $x = -3$.

1. $-8x$

For $x = 5$: $-8(5) = -40$ For $x = -3$: $-8(-3) = 24$

2. $4x + 7$

For $x = 5$: $4(5) + 7 = 20 + 7 = 27$ For $x = -3$: $4(-3) + 7 = -12 + 7 = -5$

3. $16 - 2x$

For $x = 5$: $16 - 2(5) = 16 - 10 = 6$ For $x = -3$: $16 - 2(-3) = 16 + 6 = 22$

4. $\frac{x - 5}{2}$

For $x = 5$: $\frac{5 - 5}{2} = \frac{0}{2} = 0$ For $x = -3$: $\frac{-3 - 5}{2} = \frac{-8}{2} = -4$

Summary of Results:

For $x = 5$:

1. $-8x = -40$
2. $4x + 7 = 27$
3. $16 - 2x = 6$
4. $\frac{x - 5}{2} = 0$

For $x = -3$:

1. $-8x = 24$
2. $4x + 7 = -5$
3. $16 - 2x = 22$
4. $\frac{x - 5}{2} = -4$

Would you like more details on any part of the calculations?

Here are 5 related questions to expand your understanding:

1. How do you simplify algebraic expressions like $4x + 7$?
2. What happens to expressions when substituting positive and negative values of $x$?
3. How would you solve for $x$ if you were given the result of $4x + 7$?
4. What is the effect of multiplying a variable by a negative constant, like in $-8x$?
5. How can you check your solutions to ensure they're correct?

Tip: Always substitute values into an expression carefully, following the correct order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).