https://file.aiquickdraw.com/mathbot/file/1726830318410ypfdicjc.jpg

The problem in the image asks to calculate the value of four algebraic expressions for two different values of \( x \):

1. \( x = 5 \)
2. \( x = -3 \)

The expressions are:

1. \( -8x \)
2. \( 4x + 7 \)
3. \( 16 - 2x \)
4. \( \frac{x - 5}{2} \)

Let's evaluate each of these expressions for both \( x = 5 \) and \( x = -3 \).

### 1. \( -8x \)
For \( x = 5 \):
\[
-8(5) = -40
\]
For \( x = -3 \):
\[
-8(-3) = 24
\]

### 2. \( 4x + 7 \)
For \( x = 5 \):
\[
4(5) + 7 = 20 + 7 = 27
\]
For \( x = -3 \):
\[
4(-3) + 7 = -12 + 7 = -5
\]

### 3. \( 16 - 2x \)
For \( x = 5 \):
\[
16 - 2(5) = 16 - 10 = 6
\]
For \( x = -3 \):
\[
16 - 2(-3) = 16 + 6 = 22
\]

### 4. \( \frac{x - 5}{2} \)
For \( x = 5 \):
\[
\frac{5 - 5}{2} = \frac{0}{2} = 0
\]
For \( x = -3 \):
\[
\frac{-3 - 5}{2} = \frac{-8}{2} = -4
\]

### Summary of Results:
For \( x = 5 \):
1. \( -8x = -40 \)
2. \( 4x + 7 = 27 \)
3. \( 16 - 2x = 6 \)
4. \( \frac{x - 5}{2} = 0 \)

For \( x = -3 \):
1. \( -8x = 24 \)
2. \( 4x + 7 = -5 \)
3. \( 16 - 2x = 22 \)
4. \( \frac{x - 5}{2} = -4 \)

Would you like more details on any part of the calculations?

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Here are 5 related questions to expand your understanding:
1. How do you simplify algebraic expressions like \( 4x + 7 \)?
2. What happens to expressions when substituting positive and negative values of \( x \)?
3. How would you solve for \( x \) if you were given the result of \( 4x + 7 \)?
4. What is the effect of multiplying a variable by a negative constant, like in \( -8x \)?
5. How can you check your solutions to ensure they're correct?

**Tip:** Always substitute values into an expression carefully, following the correct order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

Hitunglah nilai bentuk aljabar untuk x = 5. Lalu hitung kembali untuk x = -3.

Learn how to calculate the values of algebraic expressions such as -8x, 4x + 7, 16 - 2x, and (x - 5) / 2 for x = 5 and x = -3. This problem involves basic algebra and substitution, suitable for students in Grades 6-8.

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