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We are given that \( h(x) = 2x + 3 \) and we are asked to find the value of \( h(2a) \).

To solve for \( h(2a) \), we substitute \( x = 2a \) into the function \( h(x) \):

\[
h(2a) = 2(2a) + 3
\]
\[
h(2a) = 4a + 3
\]

Thus, the correct answer is \( 4a + 3 \), which is the first option.

Would you like any additional details or have questions?

Here are five related questions:
1. What is the value of \( h(3a) \) using the same function \( h(x) \)?
2. How would the function change if \( h(x) = 3x + 2 \)?
3. Can you find the inverse of the function \( h(x) = 2x + 3 \)?
4. What is the slope of the function \( h(x) = 2x + 3 \)?
5. If \( h(x) = 2x + 3 \), what is the value of \( h(x + 1) \)?

**Tip:** When substituting values into a function, always replace the variable with the new expression carefully, ensuring that all instances of the variable are correctly substituted.

If h(x) = 2x + 3, what is the value of h(2a)?

Learn how to calculate h(2a) for the given function h(x) = 2x + 3. This algebra problem focuses on function substitution and is suitable for students in Grades 8-10.

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