I can assist you with solving the two problems shown in the image. Let's go through each one:

Problem 11:

The “size” of a television screen is given by the length of the diagonal of the screen. What “size” is a television that is 16.2 inches high and 21.6 inches wide?

To solve this, we use the Pythagorean theorem:

$\text{Diagonal} = \sqrt{(\text{Height})^2 + (\text{Width})^2}$

Here, the height is $16.2 \, \text{inches}$ and the width is $21.6 \, \text{inches}$. Plugging in the values:

$\text{Diagonal} = \sqrt{(16.2)^2 + (21.6)^2}$

Let's calculate that.

Problem 12:

A beautiful kite is attached to the back of a boat on a 250-foot string. As the speed of the boat increases, the kite rises into the air. The kite is 200 feet behind the boat when the string is taut. What is the height of the kite above the water?

This forms a right triangle, where:

• The length of the string is the hypotenuse $c = 250 \, \text{feet}$,
• The horizontal distance (distance behind the boat) is $b = 200 \, \text{feet}$,
• The height $a$ is the unknown.

Using the Pythagorean theorem:

$a^2 + b^2 = c^2$

$a^2 + 200^2 = 250^2$

Solving for $a$:

$a = \sqrt{250^2 - 200^2}$

I'll compute both these answers now.