Math Problem Statement

A man walks 700 m due west from A to B. Then he runs 800 m in the direction

S40°W from B to C. Find the true bearing of A from C correct to the nearest degree.

Solution

To solve this problem, we need to determine the true bearing of point A from point C after the man has walked from A to B and then from B to C. Here's how to approach it:

Step 1: Determine the coordinates of points B and C

Let's assume point A is at the origin (0,0)(0, 0).

  • Point B: The man walks 700 m due west from A to B. Therefore, the coordinates of point B will be:

    B(700,0)B(-700, 0)

  • Point C: The man then runs 800 m in the direction S40W\text{S}40^\circ \text{W} from B to C. The direction S40W\text{S}40^\circ \text{W} means that the angle is measured 40° west of south.

    To find the coordinates of C, we can break down the displacement into its x and y components.

    • The displacement in the x-direction (westward) is: Displacementx=800×sin(40)\text{Displacement}_x = 800 \times \sin(40^\circ)

    • The displacement in the y-direction (southward) is: Displacementy=800×cos(40)\text{Displacement}_y = 800 \times \cos(40^\circ)

    Therefore, the coordinates of point C relative to point B are: C=B+(Displacementx,Displacementy)C = B + (\text{Displacement}_x, -\text{Displacement}_y) C=(700800×sin(40),0800×cos(40))C = (-700 - 800 \times \sin(40^\circ), 0 - 800 \times \cos(40^\circ))

Step 2: Calculate the coordinates of point C

Let's compute the x and y coordinates of C.

Displacementx=800×sin(40)800×0.6428=514.24m\text{Displacement}_x = 800 \times \sin(40^\circ) \approx 800 \times 0.6428 = 514.24 \, \text{m} Displacementy=800×cos(40)800×0.7660=612.8m\text{Displacement}_y = 800 \times \cos(40^\circ) \approx 800 \times 0.7660 = 612.8 \, \text{m}

So, the coordinates of C are: C=(700514.24,0612.8)=(1214.24,612.8)C = (-700 - 514.24, 0 - 612.8) = (-1214.24, -612.8)

Step 3: Find the true bearing of A from C

The bearing is the angle measured clockwise from the north direction to the line joining points A and C. The angle θ\theta that we need is the angle between the north direction (positive y-axis) and the line CA\overrightarrow{CA}.

We can find θ\theta using the inverse tangent (arctan) function:

θ=arctan(Change in xChange in y)=arctan(1214.24612.8)\theta = \arctan\left(\frac{|\text{Change in x}|}{|\text{Change in y}|}\right) = \arctan\left(\frac{|1214.24|}{|612.8|}\right)

θ=arctan(1214.24612.8)arctan(1.981)63.6\theta = \arctan\left(\frac{1214.24}{612.8}\right) \approx \arctan(1.981) \approx 63.6^\circ

However, this angle θ\theta is measured clockwise from the south direction (because we used the absolute values). To find the true bearing from the north:

True Bearing=180+63.6=243.6\text{True Bearing} = 180^\circ + 63.6^\circ = 243.6^\circ

Final Answer

The true bearing of A from C is approximately 244° (rounded to the nearest degree).

Would you like more details or have any further questions?

Here are 5 related questions for further practice:

  1. What is the distance between points A and C?
  2. How would the coordinates of C change if the direction was S50W\text{S}50^\circ \text{W} instead?
  3. Can you find the bearing of C from A?
  4. If the man continues to walk 600 m due south from C, what will be his new coordinates?
  5. How would you calculate the true bearing if the man had initially walked east instead of west?

Tip: Bearings are always measured clockwise from the north direction. Make sure to adjust your angle accordingly based on the quadrant in which your line lies.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Vectors

Formulas

Displacement formula in trigonometry
True bearing formula

Theorems

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Suitable Grade Level

Grades 10-12