To solve \( AB + BC = AC \), it seems you are referring to a scenario where three points \( A \), \( B \), and \( C \) lie on a straight line. In this case:

- \( AB \) is the distance between point \( A \) and point \( B \),
- \( BC \) is the distance between point \( B \) and point \( C \),
- \( AC \) is the total distance between point \( A \) and point \( C \).

If \( A \), \( B \), and \( C \) are collinear (on the same line), the total distance from \( A \) to \( C \) is the sum of the distances \( AB \) and \( BC \), which gives:
\[
AB + BC = AC
\]
Thus, no further steps are needed unless there's a more specific condition to consider (such as when points \( A \), \( B \), and \( C \) are not collinear).

Would you like to provide specific coordinates or values for \( AB \) and \( BC \) to calculate this, or ask any clarifications?

### Related Questions:
1. What if the points \( A \), \( B \), and \( C \) are not on a straight line?
2. How do you calculate distances in coordinate geometry?
3. Can the triangle inequality theorem affect this result?
4. How do you find distances between points in three-dimensional space?
5. How do you calculate distances using the Pythagorean theorem?

### Tip:
Always ensure that the points are collinear when using the relation \( AB + BC = AC \). Otherwise, the sum might be larger than \( AC \).

Learn how to find the total distance of AB + BC = AC, assuming points A, B, and C are collinear. This problem explores key geometry concepts and the formula AB + BC = AC. Suitable for students in Grades 6-8.

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