Math Problem Statement

Three consecutive odd integers have a sum of 27 . Find the integers.

Solution

Let the three consecutive odd integers be represented as:

  • xx (the first integer),
  • x+2x + 2 (the second integer),
  • x+4x + 4 (the third integer).

The sum of these integers is given as:

x+(x+2)+(x+4)=27x + (x + 2) + (x + 4) = 27

Now, simplify the equation:

x+x+2+x+4=27x + x + 2 + x + 4 = 27

3x+6=273x + 6 = 27

Subtract 6 from both sides:

3x=213x = 21

Now, divide by 3:

x=7x = 7

So, the first integer is 7. The other two integers are:

x+2=7+2=9x + 2 = 7 + 2 = 9 x+4=7+4=11x + 4 = 7 + 4 = 11

Thus, the three consecutive odd integers are 7, 9, and 11.

Would you like further details or have any questions?

Here are 5 related questions:

  1. What is the sum of three consecutive even integers if the smallest is 8?
  2. If the sum of three consecutive odd integers is 45, what are the integers?
  3. Can you find three consecutive numbers whose sum is 78?
  4. What is the formula for finding the sum of nn consecutive odd integers?
  5. How does the sum of three consecutive even integers compare to three consecutive odd integers?

Tip: Consecutive odd integers always differ by 2.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Odd Integers

Formulas

Sum of consecutive odd integers: x + (x + 2) + (x + 4)
Linear equation: ax + b = c

Theorems

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Suitable Grade Level

Grades 6-8