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The problem provided asks to find \( \tan^3 \theta \) given that \( \tan \theta = 2 \).

Here's the solution:

1. We know that \( \tan \theta = 2 \).
2. Now, we are asked to find \( \tan^3 \theta \), which means:
   \[
   \tan^3 \theta = (\tan \theta)^3 = 2^3 = 8
   \]

Thus, \( \tan^3 \theta = 8 \).

Would you like further details or have any questions?

Here are some related questions you might find helpful:
1. What are the basic properties of the tangent function?
2. How do you compute higher powers of other trigonometric functions?
3. Can you explain how to differentiate or integrate functions involving tangent?
4. What are some applications of the tangent function in real-life problems?
5. How do the tangent and cotangent functions relate to each other?

**Tip:** When raising trigonometric functions to powers, treat them like algebraic expressions by applying the exponent to the entire function value.

Solve the trigonometry problem where tan(θ) = 2 and find tan^3(θ) with a clear step-by-step explanation. This covers key trigonometric concepts and power functions, suitable for high school students in Grades 9-12.

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