Math Problem Statement

find the sum and the product form that has given the roots r+s=5/2, rs=1

Solution

Given the roots rr and ss of a quadratic equation, we know:

  • The sum of the roots, r+s=52r + s = \frac{5}{2}
  • The product of the roots, rs=1rs = 1

To find the quadratic equation, we use the standard form:

x2(r+s)x+rs=0x^2 - (r+s)x + rs = 0

Substituting the given values:

x2(52)x+1=0x^2 - \left(\frac{5}{2}\right)x + 1 = 0

So the quadratic equation is:

x252x+1=0x^2 - \frac{5}{2}x + 1 = 0

Summary:

  • Sum form: x252x+1=0x^2 - \frac{5}{2}x + 1 = 0
  • Product form: The expression above is in the expanded standard form, which is also the "product form" in this context.

Would you like more details or have any questions?

Here are 5 related questions to explore further:

  1. How would you convert this equation into a different form, like vertex form?
  2. What are the roots of the equation x252x+1=0x^2 - \frac{5}{2}x + 1 = 0?
  3. How does changing the sum or product affect the roots of a quadratic equation?
  4. What is the discriminant of this quadratic equation and what does it indicate?
  5. How can you derive the quadratic formula using this specific equation?

Tip: When working with quadratic equations, always remember that the sum and product of the roots can be directly used to write the equation. This is a quick way to check your work or create equations from given roots.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations

Formulas

Quadratic equation formula: x^2 - (r+s)x + rs = 0

Theorems

Vieta's formulas

Suitable Grade Level

Grades 9-12