The image you provided shows a problem asking for the slope and y-intercept of the line on the graph, followed by writing the equation of the line in slope-intercept form.

Here’s the solution outlined in the image:

1. Slope (m): The slope is given as 2. This is the rate of change of the line, meaning for every unit increase in $x$, $y$ increases by 2.

2. Y-intercept (b): The y-intercept is given as the point $(0, 6)$, meaning the line crosses the y-axis at $y = 6$.

3. Equation of the line: Using the slope-intercept form $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept, the equation of the line is: $y = 2x + 6$ This equation means that as $x$ increases, $y$ increases according to the slope of 2, and the line crosses the y-axis at $y = 6$.

Would you like more detailed steps or any further explanation on any part?

Here are five related questions to expand on this concept:

1. What is the general formula for finding the slope between two points on a line?
2. How do you identify the slope of a horizontal or vertical line from its graph?
3. Can you rewrite the equation $y = 2x + 6$ in standard form?
4. How would the graph change if the slope were negative?
5. If the y-intercept were $(0, -4)$ instead of $(0, 6)$, how would the equation change?

Tip: In slope-intercept form $y = mx + b$, always remember that $m$ is the slope and $b$ is the y-intercept. This form makes it easy to graph the equation.