what is the slope of a line that is perpendicular to the graph of y = -5/8x?

The slope of the line given by the equation \( y = -\frac{5}{8}x \) is \( -\frac{5}{8} \).

To find the slope of a line that is **perpendicular** to this, we use the fact that the slopes of perpendicular lines are **negative reciprocals** of each other.

The negative reciprocal of \( -\frac{5}{8} \) is \( \frac{8}{5} \).

Thus, the slope of the line perpendicular to \( y = -\frac{5}{8}x \) is \( \frac{8}{5} \).

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you find the slope of a line given two points?
2. What is the slope of a line parallel to \( y = -\frac{5}{8}x \)?
3. How do you derive the equation of a line with a given slope passing through a specific point?
4. What is the general formula for the slope of a perpendicular line?
5. Can the slope of a vertical line be expressed?

**Tip:** Always remember that perpendicular slopes multiply to give \(-1\).

Learn how to find the slope of a line that is perpendicular to the equation y = -5/8x. Understand the concept of slopes of perpendicular lines and apply the formula to solve this algebraic problem. Suitable for students in Grades 8-10.

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