Math Problem Statement

The exterior angle of a regular polygon measures 8°. How many sides does the polygon have?

Solution

The question in the image asks:

"The exterior angle of a regular polygon measures 8°. How many sides does the polygon have?"

To solve this, use the formula for the exterior angle of a regular polygon:

Exterior Angle=360n\text{Exterior Angle} = \frac{360^\circ}{n}

Where nn is the number of sides of the polygon.

Given that the exterior angle is 88^\circ:

8=360n8 = \frac{360}{n}

Now, solve for nn:

n=3608=45n = \frac{360}{8} = 45

Therefore, the polygon has 45 sides.

Would you like more details or explanations on this?

Here are 5 related questions:

  1. What is the formula for the interior angle of a regular polygon?
  2. How do you find the sum of interior angles of a polygon?
  3. What is the relationship between interior and exterior angles of a polygon?
  4. How would you solve for the number of sides if given an interior angle?
  5. Can a regular polygon have an exterior angle greater than 90°?

Tip: The sum of all exterior angles of any polygon, regardless of the number of sides, is always 360360^\circ.

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Math Problem Analysis

Mathematical Concepts

Polygon Geometry
Exterior Angles
Regular Polygons

Formulas

Exterior Angle = 360° / n (where n is the number of sides)

Theorems

Sum of exterior angles of any polygon is always 360°

Suitable Grade Level

Grades 8-10