https://file.aiquickdraw.com/mathbot/file/1727112411809xfffazk7.jpg

The question in the image asks:

"The exterior angle of a regular polygon measures 8°. How many sides does the polygon have?"

To solve this, use the formula for the exterior angle of a regular polygon:

\[
\text{Exterior Angle} = \frac{360^\circ}{n}
\]

Where \( n \) is the number of sides of the polygon.

Given that the exterior angle is \( 8^\circ \):

\[
8 = \frac{360}{n}
\]

Now, solve for \( n \):

\[
n = \frac{360}{8} = 45
\]

Therefore, the polygon has **45 sides**.

Would you like more details or explanations on this?

Here are 5 related questions:
1. What is the formula for the interior angle of a regular polygon?
2. How do you find the sum of interior angles of a polygon?
3. What is the relationship between interior and exterior angles of a polygon?
4. How would you solve for the number of sides if given an interior angle?
5. Can a regular polygon have an exterior angle greater than 90°?

**Tip**: The sum of all exterior angles of any polygon, regardless of the number of sides, is always \(360^\circ\).

The exterior angle of a regular polygon measures 8°. How many sides does the polygon have?

Solve for the number of sides in a regular polygon when given that the exterior angle measures 8°. This problem covers geometric concepts including exterior angles and polygons, suitable for students in Grades 8-10.

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