https://file.aiquickdraw.com/mathbot/file/1728582683108duio3ldz.jpg

To solve for \(\sec A\) in the right triangle, we need to understand the following:

In a right triangle, the secant (\(\sec\)) of an angle is defined as the ratio of the hypotenuse to the adjacent side of the angle.

### Given Data:
- Hypotenuse = \(5\)
- Adjacent side to angle \(A\) = \(4\)

### Solution:
\[
\sec A = \frac{\text{Hypotenuse}}{\text{Adjacent side}} = \frac{5}{4}
\]

Thus, the correct answer is:
\[
\sec A = \frac{5}{4}
\]

Would you like a detailed explanation on how secant relates to other trigonometric functions, or do you have any other questions?

---

### Follow-up Questions:
1. How would you find \(\cos A\) in this triangle?
2. What would be \(\sin A\) for this triangle?
3. Can you calculate \(\tan A\) using the given sides?
4. How would you find \(\csc A\) if needed?
5. Is it possible to find angle \(A\) in degrees?

#### Tip:
Remember, \(\sec\) is the reciprocal of \(\cos\). So, \(\sec A = \frac{1}{\cos A}\). This relationship can simplify your calculations when dealing with trigonometric functions.

For the right triangle shown, find sec A.

Solve for sec A in a right triangle where the hypotenuse is 5 and the adjacent side to angle A is 4. This problem covers key trigonometric concepts such as secant and triangle ratios, suitable for Grade 9-10 students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation