Math Problem Statement

1/3 not 1/2

Solution

To solve the problem given in the image, let's address each part in turn.

Q1: Find the Relative Extreme of the Function g(x)=3x1/3g(x) = 3 - x^{1/3}

To find the relative extrema of the function g(x)=3x1/3g(x) = 3 - x^{1/3}, we need to:

  1. Find the first derivative g(x)g'(x):
    The first derivative will help us determine where the slope of the function is zero or undefined, which corresponds to potential relative extrema.

    g(x)=3x1/3g(x) = 3 - x^{1/3} Taking the derivative with respect to xx:

    g(x)=013x2/3=13x2/3=13x2/3g'(x) = 0 - \frac{1}{3}x^{-2/3} = -\frac{1}{3}x^{-2/3} = -\frac{1}{3x^{2/3}}

  2. Set g(x)=0g'(x) = 0 to find critical points:
    Since g(x)=13x2/3g'(x) = -\frac{1}{3x^{2/3}}, setting this equal to zero does not yield any real solutions because the function is undefined at x=0x = 0. This means there are no points where the derivative is zero, but we still need to check the behavior around x=0x = 0.

  3. Analyze the sign of g(x)g'(x):

    • For x>0x > 0, g(x)g'(x) is negative, which means the function is decreasing.
    • For x<0x < 0, g(x)g'(x) is positive, which means the function is increasing.

    At x=0x = 0, the derivative is undefined, but the function changes from increasing to decreasing, indicating a cusp point. Therefore, x=0x = 0 is a relative maximum.

Q2: Sketch the Graph

Given the analysis above:

  • As xx \to -\infty, g(x)g(x) increases without bound.
  • As xx \to \infty, g(x)g(x) decreases towards negative infinity.
  • There is a relative maximum at x=0x = 0, and g(0)=3g(0) = 3.

The graph of g(x)=3x1/3g(x) = 3 - x^{1/3} will have a cusp at x=0x = 0 with a maximum at (0,3)(0, 3). The function is increasing on the left of x=0x = 0 and decreasing on the right.

Would you like a more detailed explanation, or do you have any specific questions?

Here are some related questions you might find helpful:

  1. How can you determine whether a function has a cusp, corner, or inflection point at a critical point?
  2. What are the implications of having a derivative that is undefined at a certain point?
  3. How does the behavior of g(x)g(x) as xx approaches positive and negative infinity influence the graph?
  4. Can you find the second derivative of g(x)g(x) and use it to confirm the concavity?
  5. How do changes in the function g(x)=3x1/3g(x) = 3 - x^{1/3} affect its relative extrema?

Tip: Understanding the behavior of the first derivative is key to identifying and classifying relative extrema, cusps, and inflection points.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Relative Extrema

Formulas

First derivative
Derivative rules

Theorems

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Suitable Grade Level

Undergraduate