Math Problem Statement

d) Un rectángulo es tal que uno de su lado menor es 26 cm menos que los 5/6 del otro lado y tiene un perímetro de 124 cm. Calcule las medidas de sus lados.

Solution

Let's solve the problem step by step:

Step 1: Define variables

Let:

  • xx be the length of the longer side of the rectangle.
  • yy be the length of the shorter side of the rectangle.

Step 2: Set up the equations

According to the problem:

  1. The shorter side yy is 26 cm less than 56\frac{5}{6} of the longer side xx: y=56x26y = \frac{5}{6}x - 26

  2. The perimeter of the rectangle is 124 cm: 2x+2y=1242x + 2y = 124 Simplifying this equation: x+y=62x + y = 62

Step 3: Substitute and solve

Substituting y=56x26y = \frac{5}{6}x - 26 into x+y=62x + y = 62: x+(56x26)=62x + \left(\frac{5}{6}x - 26\right) = 62 x+56x26=62x + \frac{5}{6}x - 26 = 62 Combine like terms: 116x=88\frac{11}{6}x = 88 Multiply both sides by 611\frac{6}{11}: x=88611=48x = \frac{88 \cdot 6}{11} = 48

Step 4: Find yy

Substituting x=48x = 48 back into y=56x26y = \frac{5}{6}x - 26: y=56(48)26y = \frac{5}{6}(48) - 26 y=4026y = 40 - 26 y=14y = 14

Final Answer

The dimensions of the rectangle are:

  • Longer side: 4848 cm
  • Shorter side: 1414 cm

Would you like more details or have any questions?

5 Relative Questions

  1. How do you verify the correctness of these measurements?
  2. What would the area of this rectangle be?
  3. How would the problem change if the perimeter was different?
  4. How can we generalize this method for other rectangle problems?
  5. What happens if the ratio between the sides is altered?

Tip

Always double-check your equations and substitute back to verify that your solution satisfies all given conditions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Geometry

Formulas

Perimeter of a rectangle: P = 2x + 2y
Relationship between sides: y = (5/6)x - 26

Theorems

Linear equation solving
Geometric properties of rectangles

Suitable Grade Level

Grades 7-9