Math Problem Statement

Find only the rational zeros.

f left parenthesis x right parenthesis equals x Superscript 5 Baseline minus 3 x Superscript 4 Baseline plus 2 x cubed plus 18 x squared minus 99 x plus 81f(x)=x5−3x4+2x3+18x2−99x+81

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Part 1

Select the correct choice below and fill in any answer boxes within your choice.

A.

The rational zeros are

enter your response here.

​(Use a comma to separate answers as​ needed.)

B.

No rational zeros exist.

Solution

To find the rational zeros of the polynomial f(x)=x53x4+2x3+18x299x+81f(x) = x^5 - 3x^4 + 2x^3 + 18x^2 - 99x + 81, we can use the Rational Root Theorem.

Rational Root Theorem:

The possible rational roots (zeros) of the polynomial are of the form: Possible rational roots=factors of the constant termfactors of the leading coefficient\text{Possible rational roots} = \frac{\text{factors of the constant term}}{\text{factors of the leading coefficient}} For f(x)=x53x4+2x3+18x299x+81f(x) = x^5 - 3x^4 + 2x^3 + 18x^2 - 99x + 81:

  • The constant term is 81, so the factors of 81 are: ±1,±3,±9,±27,±81\pm 1, \pm 3, \pm 9, \pm 27, \pm 81
  • The leading coefficient is 1, so the factors of 1 are: ±1\pm 1

Thus, the possible rational roots are: ±1,±3,±9,±27,±81\pm 1, \pm 3, \pm 9, \pm 27, \pm 81

Testing the Possible Rational Roots:

We substitute each possible rational root into the polynomial f(x)f(x) to check if it equals zero.

  1. Testing x=1x = 1: f(1)=153(14)+2(13)+18(12)99(1)+81=13+2+1899+81=0f(1) = 1^5 - 3(1^4) + 2(1^3) + 18(1^2) - 99(1) + 81 = 1 - 3 + 2 + 18 - 99 + 81 = 0 So, x=1x = 1 is a rational zero.

  2. Testing x=1x = -1: f(1)=(1)53(1)4+2(1)3+18(1)299(1)+81=132+18+99+81=1920f(-1) = (-1)^5 - 3(-1)^4 + 2(-1)^3 + 18(-1)^2 - 99(-1) + 81 = -1 - 3 - 2 + 18 + 99 + 81 = 192 \neq 0 So, x=1x = -1 is not a rational zero.

  3. Testing x=3x = 3: f(3)=353(34)+2(33)+18(32)99(3)+81=243243+54+162297+81=0f(3) = 3^5 - 3(3^4) + 2(3^3) + 18(3^2) - 99(3) + 81 = 243 - 243 + 54 + 162 - 297 + 81 = 0 So, x=3x = 3 is a rational zero.

  4. Testing x=3x = -3: f(3)=(3)53(34)+2(33)+18(32)99(3)+81=24324354+162+297+81=0f(-3) = (-3)^5 - 3(-3^4) + 2(-3^3) + 18(-3^2) - 99(-3) + 81 = -243 - 243 - 54 + 162 + 297 + 81 = 0 So, x=3x = -3 is a rational zero.

Thus, the rational zeros of the polynomial are 1,3,3\boxed{1, 3, -3}.

Final Answer:

The rational zeros are 1,3,3\boxed{1, 3, -3}.

Would you like more details or have any questions?


Here are 5 related questions to expand on this:

  1. How does the Rational Root Theorem help identify potential rational zeros?
  2. What is the process to fully factor this polynomial after finding the rational zeros?
  3. Can there be irrational or complex zeros in addition to the rational ones?
  4. How can synthetic division be used to simplify polynomial zero-finding after identifying a root?
  5. What is the difference between rational and real zeros in the context of this problem?

Tip: When testing possible rational roots, it can be faster to use synthetic division after finding a zero to reduce the polynomial degree.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomials
Rational Root Theorem
Zero-finding

Formulas

Rational Root Theorem: Possible rational roots = (factors of constant term)/(factors of leading coefficient)

Theorems

Rational Root Theorem

Suitable Grade Level

Grades 10-12