https://file.aiquickdraw.com/mathbot/file/1729176916861y5bylfog.jpg

The problem in the image can be translated as follows:

The average score for male students is 78, and the average score for female students is 70. If the overall class average score is 73, what is the ratio of the number of male students to female students?

We can solve this problem using the concept of weighted averages.

Let:
- \( x \) be the number of male students,
- \( y \) be the number of female students.

The overall class average is given as:

\[
\frac{78x + 70y}{x + y} = 73
\]

Now, multiplying both sides by \( x + y \) to eliminate the denominator:

\[
78x + 70y = 73(x + y)
\]

Expanding the right-hand side:

\[
78x + 70y = 73x + 73y
\]

Now, subtract \( 73x \) and \( 73y \) from both sides:

\[
78x - 73x = 73y - 70y
\]

Simplifying this:

\[
5x = 3y
\]

Thus, the ratio of the number of male students to female students is:

\[
\frac{x}{y} = \frac{3}{5}
\]

Therefore, the correct answer is:

**Option d: 5:3**

Would you like more details or have any further questions? 

Here are five related questions to think about:
1. How does the concept of weighted averages apply to this kind of problem?
2. What other types of problems can be solved using a similar approach?
3. How would the ratio change if the overall class average were different?
4. Can you generalize this formula to other scenarios involving different averages?
5. How does the method change if more than two groups are involved?

**Tip**: Always check the consistency of the average by calculating the weighted sum of the individual group averages.

Nilai rata-rata siswa putra adalah 78 dan nilai rata-rata siswa putri adalah 70. Jika nilai rata-rata dalam kelas adalah 73, maka perbandingannya banyaknya siswa putra dengan siswa putri adalah?

Learn how to find the ratio of male to female students using weighted averages. Given that the average score of male students is 78, female students is 70, and the overall class average is 73, this problem explains how to apply algebraic concepts and solve for the ratio.

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