Math Problem Statement

Given P(A) = 7/20 and P(A or B) = 231/400, find P(B).

Solution

To solve this problem, we will use the formula for the union of two probabilities:

P(A or B)=P(A)+P(B)P(A and B)P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)

From the given information:

  • P(A)=720P(A) = \frac{7}{20},
  • P(A or B)=231400P(A \text{ or } B) = \frac{231}{400},
  • We need to find P(B)P(B).

Assume P(A and B)=xP(A \text{ and } B) = x. The formula then becomes:

231400=720+P(B)x\frac{231}{400} = \frac{7}{20} + P(B) - x

Step 1: Convert P(A)P(A) to a denominator of 400

P(A)=720=140400.P(A) = \frac{7}{20} = \frac{140}{400}.

The equation now becomes: 231400=140400+P(B)x.\frac{231}{400} = \frac{140}{400} + P(B) - x.

Step 2: Rearrange the equation

Rearranging for P(B)P(B): P(B)=231400140400+x.P(B) = \frac{231}{400} - \frac{140}{400} + x.

Simplify: P(B)=91400+x.P(B) = \frac{91}{400} + x.

Step 3: Solve for P(A and B)P(A \text{ and } B) if more information is given

To fully solve for P(B)P(B), we would need the value of P(A and B)P(A \text{ and } B) (denoted as xx). If this is independent or additional information is provided, we can substitute it to find P(B)P(B).

Would you like me to assume independence (P(A and B)=P(A)P(B)P(A \text{ and } B) = P(A) \cdot P(B)) or do you have additional information about P(A and B)P(A \text{ and } B)?


Would you like further clarification or a deeper explanation of any steps? Here are 5 related questions to explore:

  1. What is the impact of independence on this type of problem?
  2. How is the formula for union probability derived?
  3. What are the possible ranges for P(B)P(B) in this case?
  4. How does knowing P(A and B)P(A \text{ and } B) help us finalize P(B)P(B)?
  5. Can you show a real-life example of using this formula in practice?

Tip: When solving probability problems, always check whether the events are independent or dependent, as this greatly affects the calculation.

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Math Problem Analysis

Mathematical Concepts

Probability
Set Theory
Union and Intersection of Events

Formulas

P(A or B) = P(A) + P(B) - P(A and B)

Theorems

Addition Rule for Probabilities

Suitable Grade Level

Grades 9-12