Math Problem Statement

Find the perimeter with these vertices (3,5), (4,2), (3,1), (-4,-2).

Solution

The image asks to find the perimeter of a polygon given the vertices:

  • (3,5)
  • (4,2)
  • (3,1)
  • (-4,-2)

To find the perimeter, we need to calculate the distance between each consecutive pair of points and then add up the distances. The distance between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step-by-Step Calculation:

  1. Distance between (3,5) and (4,2): d1=(43)2+(25)2=12+(3)2=1+9=10d_1 = \sqrt{(4 - 3)^2 + (2 - 5)^2} = \sqrt{1^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10}

  2. Distance between (4,2) and (3,1): d2=(34)2+(12)2=(1)2+(1)2=1+1=2d_2 = \sqrt{(3 - 4)^2 + (1 - 2)^2} = \sqrt{(-1)^2 + (-1)^2} = \sqrt{1 + 1} = \sqrt{2}

  3. Distance between (3,1) and (-4,-2): d3=(43)2+(21)2=(7)2+(3)2=49+9=58d_3 = \sqrt{(-4 - 3)^2 + (-2 - 1)^2} = \sqrt{(-7)^2 + (-3)^2} = \sqrt{49 + 9} = \sqrt{58}

  4. Distance between (-4,-2) and (3,5): d4=(3(4))2+(5(2))2=(3+4)2+(5+2)2=72+72=49+49=98d_4 = \sqrt{(3 - (-4))^2 + (5 - (-2))^2} = \sqrt{(3 + 4)^2 + (5 + 2)^2} = \sqrt{7^2 + 7^2} = \sqrt{49 + 49} = \sqrt{98}

Now, add the distances together to get the perimeter:

Perimeter=10+2+58+98\text{Perimeter} = \sqrt{10} + \sqrt{2} + \sqrt{58} + \sqrt{98}

You can compute this numerically for the final perimeter value.

Would you like me to calculate the final value for the perimeter or explain any part of this further?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Distance Formula

Formulas

Distance formula: d = √((x2 - x1)² + (y2 - y1)²)

Theorems

Distance between two points

Suitable Grade Level

Grades 9-11