Let's solve the problems in the image:

Part a: Rectangle

We are given a rectangle with:

• Length $l = 5.5 \, \text{cm}$
• Width $w = 2 \, \text{cm}$

Perimeter of a rectangle is calculated as: $P = 2(l + w)$ Substituting the values: $P = 2(5.5 + 2) = 2(7.5) = 15 \, \text{cm}$

Area of a rectangle is calculated as: $A = l \times w$ Substituting the values: $A = 5.5 \times 2 = 11 \, \text{cm}^2$

Part b: Right Triangle

We are given a right triangle with:

• One leg $a = 2.8 \, \text{km}$
• Another leg $b = 4.9 \, \text{km}$
• Hypotenuse $c = 6.9 \, \text{km}$

Perimeter of the triangle is calculated as: $P = a + b + c$ Substituting the values: $P = 2.8 + 4.9 + 6.9 = 14.6 \, \text{km}$

Area of a right triangle is calculated as: $A = \frac{1}{2} \times a \times b$ Substituting the values: $A = \frac{1}{2} \times 2.8 \times 4.9 = 6.86 \, \text{km}^2$

Would you like further details or clarification on any step? Here are some related questions for practice:

1. How do you find the perimeter and area of a square?
2. What formula do you use for the area of a circle?
3. Can the Pythagorean theorem be used for any triangle?
4. How does changing the dimensions of a rectangle affect its perimeter and area?
5. If the height of a triangle is doubled, how is its area affected?

Tip: In right triangles, the Pythagorean theorem can help verify if the given sides form a right triangle.