Math Problem Statement

Consider the following data:

x 1 2 3 4 5 P(X=x) 0.3 0.1 0.2 0.1 0.3

Step 5 of 5: Find the value of P(X>2) . Round your answer to one decimal place.

Solution

To find P(X>2)P(X > 2), we need to sum the probabilities for all values of XX greater than 2. From the given data:

  • P(X=3)=0.2P(X = 3) = 0.2
  • P(X=4)=0.1P(X = 4) = 0.1
  • P(X=5)=0.3P(X = 5) = 0.3

So,

P(X>2)=P(X=3)+P(X=4)+P(X=5)P(X > 2) = P(X = 3) + P(X = 4) + P(X = 5) P(X>2)=0.2+0.1+0.3=0.6P(X > 2) = 0.2 + 0.1 + 0.3 = 0.6

Therefore, the value of P(X>2)P(X > 2) is 0.6.

Would you like further details on this process, or do you have any questions about it?

Here are some related questions to deepen your understanding:

  1. What is the definition of a probability distribution?
  2. How do you calculate P(X<4)P(X < 4)?
  3. What is the formula to find the expected value of a discrete random variable?
  4. How do you calculate the variance for a discrete probability distribution?
  5. How would the result change if P(X=5)P(X=5) were 0.4 instead of 0.3?

Tip: To find probabilities like P(X>a)P(X > a), just sum the individual probabilities for all values of XX greater than aa.

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Math Problem Analysis

Mathematical Concepts

Probability
Discrete Probability Distribution

Formulas

P(X > a) = P(X = a+1) + P(X = a+2) + ...

Theorems

Addition Rule for Probabilities

Suitable Grade Level

Grades 9-11