We are given the following information:

• $\frac{2}{7}$ of the students have blue eyes.
• $\frac{1}{3}$ of the class has green eyes.
• 6 students have blue eyes.

We are asked to find how many students have green eyes.

Step 1: Calculate the total number of students in the class

Let $x$ represent the total number of students in the class. Since $\frac{2}{7}$ of the students have blue eyes and this is equal to 6 students, we can set up the equation: $\frac{2}{7} \times x = 6$ To solve for $x$, multiply both sides by $\frac{7}{2}$: $x = 6 \times \frac{7}{2} = 21$ So, the total number of students in the class is 21.

Step 2: Find the number of students with green eyes

We are told that $\frac{1}{3}$ of the class has green eyes. Thus, the number of students with green eyes is: $\frac{1}{3} \times 21 = 7$

Final Answer:

The number of students with green eyes is 7.

Would you like further details or have any other questions?

Here are 5 related questions you might find useful:

1. What if $\frac{1}{4}$ of the students had brown eyes instead of green?
2. How would you calculate the number of students if 8 had blue eyes?
3. What is the combined fraction of students with blue and green eyes?
4. How can you check if the total of blue and green-eyed students adds up correctly?
5. How many students in the class do not have blue or green eyes?

Tip: Always verify that the fractions sum up logically when dealing with fractions of a group!