To solve this problem, we have two similar rectangles. In similar figures, the ratio of the corresponding sides is the same.

For the smaller rectangle:

• One side is 12, and the other is 18.

For the larger rectangle:

• One side is 16, and the missing side is $x$.

We can set up a proportion between the corresponding sides: $\frac{12}{18} = \frac{16}{x}$

Now let's solve for $x$.

I'll calculate that.The missing side $x$ in the larger rectangle is 24.

Would you like a detailed explanation of the steps involved or have any other questions?

Here are 5 related questions to expand on this concept:

1. How do we determine if two figures are similar?
2. What happens to the area of a figure when its dimensions are scaled?
3. Can this same method be used for triangles or other polygons?
4. What would the ratio of the perimeters be in similar figures?
5. How do ratios apply in real-world scaling problems, like models or maps?

Tip: Always ensure that corresponding sides are compared correctly when setting up proportions in similar figures.