To find the missing angle $x$ in the triangle, we will use the fact that the sum of the interior angles of a triangle is always $180^\circ$.

The given angles are $60^\circ$ and $80^\circ$.

Let's solve for $x$:

$x = 180^\circ - (60^\circ + 80^\circ)$ $x = 180^\circ - 140^\circ$ $x = 40^\circ$

Thus, the missing angle $x$ is $40^\circ$.

Would you like more details on how this process works or have any further questions? Here are some related questions to explore further:

1. How can you verify the sum of angles in a triangle?
2. What happens if one angle in a triangle exceeds 90 degrees?
3. Can a triangle have more than one angle greater than 90 degrees? Why or why not?
4. How would you classify this triangle based on its angles?
5. How can this concept be applied to polygons with more than three sides?

Tip: Always remember that the sum of interior angles in any polygon can be found using the formula $180(n-2)^\circ$, where $n$ is the number of sides.