To find the midpoint of a line segment with endpoints $(-10, 8)$ and $(-4, -2)$, you can use the midpoint formula:

$\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)$

Here, $(x_1, y_1)$ is $(-10, 8)$ and $(x_2, y_2)$ is $(-4, -2)$.

Substituting the values:

$\text{Midpoint} = \left( \frac{-10 + (-4)}{2}, \frac{8 + (-2)}{2} \right)$

Simplify the expressions:

$\text{Midpoint} = \left( \frac{-14}{2}, \frac{6}{2} \right)$

$\text{Midpoint} = (-7, 3)$

So, the midpoint of the segment is $(-7, 3)$.

Would you like more details or have any questions?

Here are some related questions:

1. How do you find the distance between the same endpoints?
2. What is the slope of the line segment connecting the given endpoints?
3. How do you find the equation of the line passing through these endpoints?
4. What are the coordinates of a point that divides the segment in a ratio of 2:3?
5. How can you verify that $(-7, 3)$ is indeed the midpoint?

Tip: Always check your work by substituting back into the original equation to ensure accuracy!