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To find the **median** of the marks in the class, we first need to organize the given marks in **ascending order**. The data provided is for 11 students who passed, as 4 out of 15 students failed.

The given marks are:
38, 45, 63, 35, 81, 99, 78, 57, 92, 39, 48

### Step 1: Arrange the marks in ascending order
Sorted marks:
35, 38, 39, 45, 48, 57, 63, 78, 81, 92, 99

### Step 2: Find the median
Since there are 11 students, the median will be the middle value, which is the 6th value in the ordered list.

The 6th value is **57**.

Thus, the **median marks** of the class are **57**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How do we calculate the median for an even number of students?
2. What is the difference between mean and median?
3. How does the median differ when outliers are present in the dataset?
4. What happens to the median if a few more students' marks are added?
5. Can median be used to determine the overall performance of the class?

**Tip:** Median is less sensitive to extreme values (outliers) compared to the mean, making it a better measure of central tendency in skewed distributions.

In a class of 15 students, 4 students failed and those who passed had marks 38, 45, 63, 35, 81, 99, 78, 57, 92, 39, 48. Find the median marks of the class.

Learn how to find the median of a data set in a class where 11 students passed with varying marks. Follow the step-by-step process to arrange the data and determine the middle value, ideal for students in Grades 6-8.

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