To solve for $m \angle 2$ in this problem, let's go through the information provided:

1. We know: $m \angle ABD = 67^\circ$
2. The problem states that: $m \angle 1 \text{ is } 5^\circ \text{ more than } m \angle 2$

Let’s set $m \angle 2 = x$. Then, $m \angle 1$ would be: $m \angle 1 = x + 5$

Since $\angle 1$ and $\angle 2$ together make up $\angle ABD$, we can set up the equation: $x + (x + 5) = 67$

Step 1: Solve for $x$

$2x + 5 = 67$ $2x = 67 - 5$ $2x = 62$ $x = 31$

Step 2: Answer

Thus, $m \angle 2 = 31^\circ$.

Would you like more details or have any questions?

Related Questions

1. How would you solve if $m \angle 1$ was less than $m \angle 2$ by a certain degree?
2. What if $m \angle ABD$ was given in terms of another angle?
3. How does angle addition work in cases where there are multiple intersecting angles?
4. What if the total angle was not 67° but another value?
5. How can you check the answer to ensure it's accurate?

Tip

Always write down relationships and equations step-by-step to avoid errors in solving angle problems.